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It seems 200 MB of RAM are used from the box, according to the whitepaper. And to get to 1700,there are 100 more that cannot be explained. But after my way of thinking (even though I am not sure it applies to RAM as it does to internal memory), from about 1.9 GB available, you end up with the 1.7 for normal use.

alexdon

Don_Quixote

Thanks guys! They must have found a new meaning to dynamic random access memory 😉

Uliwooly

Anytime

Thommo

This is quite simple really you could go a route which most people do and multiply 2GB by 1000 and then divide it by 1024 giving 1.95GB which is readable but is wrong.

There are two correct ways after doing some math is to multiply 2 by 0.9313226 giving 1.86 readable memory, When you start using TB you multiply the amount of TB by 0.9094947 so for example if you have one, A 2TB drive multiplied by 0.9094947 gives you 1.81TB readable

Another way which is also correct is to multiply 2 by 1000, 3 times IE: 2x1000x1000x1000 then divide that by 1024 and again 1024 and again 1024 giving the same answer 1.86GB readable

These are how you get actual readable memory as to what is advertised - Try it yourself on your Pc's hard drive using these calculations

_alexdon_

@Thommo it means I was on the right path, I did explain this in the other thread for Z1 compact.

alexdon

Don_Quixote

It seems I'm ancient :'(
New IEC Standard
bit bit 0 or 1
byte B 8 bits
kibibit Kibit 1024 bits
kilobit kbit 1000 bits
kibibyte (binary) KiB 1024 bytes
kilobyte (decimal) kB 1000 bytes
megabit Mbit 1000 kilobits
mebibyte (binary) MiB 1024 kibibytes
megabyte (decimal) MB 1000 kilobytes
gigabit Gbit 1000 megabits
gibibyte (binary) GiB 1024 mebibytes
gigabyte (decimal) GB 1000 megabytes

Although they are only referring to storagespace and not DRAM 0:-)

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